Exercise logic.propositional.dnf
Description
Proposition to DNF
((~q /\ ~(p -> q) /\ ~q /\ ~(p -> q) /\ ~q /\ ~(p -> q)) -> p) || ((~q /\ ~(p -> q) /\ ~q /\ ~(p -> q) /\ ~(p -> q) /\ ~q /\ ~(p -> q)) -> p)
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Path 1
path | [0, 2, 0, 0, 0, 5, 5, 6, 5, 6, 1, 2] |
steps | 12 |
major rules | 1 |
active labels |
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