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Exercise logic.propositional.dnf
Description
Proposition to DNF
((p || q || p || q) /\ (r <-> (p || F))) || ((p || q || p || q) /\ (r <-> (p || F)))
ready: no
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onefirst
allfirsts (1)
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derivation
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Path 1
path
[0, 0, 0]
steps
3
major rules
1
active labels
dnf
orrules
enter dnf
,
enter orrules
,
logic.propositional.falsezeroor