Exercise logic.propositional.dnf
Description
Proposition to DNF
((~q /\ ~(p -> q) /\ ~q /\ ~(p -> q) /\ ~((p || p) -> q) /\ ~q /\ ~(p -> q)) || (~q /\ ~(p -> q) /\ ~q /\ ~(p -> q) /\ ~((p || p) -> q) /\ ~q /\ ~(p -> q))) -> p
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