Exercise logic.propositional.dnf.unicode
Description
Proposition to DNF (unicode support)
Derivation
![](http://ideas.cs.uu.nl/images/external.png)
F ∨ (¬((q → p) ∨ ((q → p) ∧ (q → p))) ↔ ((r ↔ s) ∨ ¬s))
⇒ logic.propositional.idempandF ∨ (¬((q → p) ∨ (q → p)) ↔ ((r ↔ s) ∨ ¬s))
⇒ logic.propositional.defimplF ∨ (¬((q → p) ∨ ¬q ∨ p) ↔ ((r ↔ s) ∨ ¬s))