Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

F || (F /\ r) || ((q || ~~p) /\ (q || p))

⇒ logic.propositional.notnot

F || (F /\ r) || ((q || p) /\ (q || p))

⇒ logic.propositional.idempand

F || (F /\ r) || q || p