Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

~~(~~(F /\ r) || ~~(q || ~~((F || ~~p) /\ ~~p)))

⇒ logic.propositional.notnot

~~(F /\ r) || ~~(q || ~~((F || ~~p) /\ ~~p))

⇒ logic.propositional.notnot

(F /\ r) || ~~(q || ~~((F || ~~p) /\ ~~p))

⇒ logic.propositional.falsezeroand

F || ~~(q || ~~((F || ~~p) /\ ~~p))

⇒ logic.propositional.falsezeroor

~~(q || ~~((F || ~~p) /\ ~~p))

⇒ logic.propositional.notnot

q || ~~((F || ~~p) /\ ~~p)

⇒ logic.propositional.notnot

q || ((F || ~~p) /\ ~~p)

⇒ logic.propositional.absorpand

q || ~~p

⇒ logic.propositional.notnot

q || p