Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

~~(p || p) || q || (F /\ r) || q || ~~p

⇒ logic.propositional.falsezeroand

~~(p || p) || q || F || q || ~~p

⇒ logic.propositional.falsezeroor

~~(p || p) || q || q || ~~p

⇒ logic.propositional.idempor

~~(p || p) || q || ~~p

⇒ logic.propositional.notnot

p || p || q || ~~p

⇒ logic.propositional.idempor

p || q || ~~p

⇒ logic.propositional.notnot

p || q || p