Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

~~(p /\ p) || ((F || q) /\ (r || q))

⇒ logic.propositional.falsezeroor

~~(p /\ p) || (q /\ (r || q))

⇒ logic.propositional.absorpand

~~(p /\ p) || q

⇒ logic.propositional.notnot

(p /\ p) || q

⇒ logic.propositional.idempand

p || q