Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
~~(F || ((q || ~~p || F) /\ (q || ~~p || r)) || q || ~~p)
⇒ logic.propositional.notnotF || ((q || ~~p || F) /\ (q || ~~p || r)) || q || ~~p
⇒ logic.propositional.falsezeroor((q || ~~p || F) /\ (q || ~~p || r)) || q || ~~p
⇒ logic.propositional.falsezeroor((q || ~~p) /\ (q || ~~p || r)) || q || ~~p
⇒ logic.propositional.absorpandq || ~~p || q || ~~p
⇒ logic.propositional.idemporq || ~~p
⇒ logic.propositional.notnotq || p