Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
![](http://ideas.cs.uu.nl/images/external.png)
~~(F /\ r) || q || (~~p /\ ~~p) || ~~(F /\ r) || q || (~~p /\ ~~p)
⇒ logic.propositional.idempand~~(F /\ r) || q || ~~p || ~~(F /\ r) || q || (~~p /\ ~~p)
⇒ logic.propositional.idempand~~(F /\ r) || q || ~~p || ~~(F /\ r) || q || ~~p
⇒ logic.propositional.idempor~~(F /\ r) || q || ~~p
⇒ logic.propositional.notnot(F /\ r) || q || ~~p
⇒ logic.propositional.falsezeroandF || q || ~~p
⇒ logic.propositional.falsezeroorq || ~~p
⇒ logic.propositional.notnotq || p