Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

~~((q /\ q) || ~~p) || F || (F /\ r)

⇒ logic.propositional.absorpor

~~((q /\ q) || ~~p) || F

⇒ logic.propositional.falsezeroor

~~((q /\ q) || ~~p)

⇒ logic.propositional.notnot

(q /\ q) || ~~p

⇒ logic.propositional.idempand

q || ~~p

⇒ logic.propositional.notnot

q || p