Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
![](http://ideas.cs.uu.nl/images/external.png)
~~((F /\ r) || q || ~~p || ((F || q || ~~p) /\ (r || q || ~~p)))
⇒ logic.propositional.falsezeroor~~((F /\ r) || q || ~~p || ((q || ~~p) /\ (r || q || ~~p)))
⇒ logic.propositional.absorpand~~((F /\ r) || q || ~~p || q || ~~p)
⇒ logic.propositional.notnot~~((F /\ r) || q || p || q || ~~p)
⇒ logic.propositional.notnot~~((F /\ r) || q || p || q || p)