Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
![](http://ideas.cs.uu.nl/images/external.png)
~~((F /\ r) || q || (~~(p || F) /\ ~~(p || F)))
⇒ logic.propositional.idempand~~((F /\ r) || q || ~~(p || F))
⇒ logic.propositional.notnot~~((F /\ r) || q || p || F)
⇒ logic.propositional.falsezeroor~~((F /\ r) || q || p)