Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

~~((F /\ r) || q || ((~~p || ~~p) /\ (~~p || ~~p)))

⇒ logic.propositional.notnot

(F /\ r) || q || ((~~p || ~~p) /\ (~~p || ~~p))

⇒ logic.propositional.falsezeroand

F || q || ((~~p || ~~p) /\ (~~p || ~~p))

⇒ logic.propositional.falsezeroor

q || ((~~p || ~~p) /\ (~~p || ~~p))

⇒ logic.propositional.idempand

q || ~~p || ~~p

⇒ logic.propositional.idempor

q || ~~p

⇒ logic.propositional.notnot

q || p