Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
![](http://ideas.cs.uu.nl/images/external.png)
~~((F /\ r) || ((q || ~~(p || F)) /\ (q || ~~(p || F))))
⇒ logic.propositional.notnot(F /\ r) || ((q || ~~(p || F)) /\ (q || ~~(p || F)))
⇒ logic.propositional.falsezeroandF || ((q || ~~(p || F)) /\ (q || ~~(p || F)))
⇒ logic.propositional.falsezeroor(q || ~~(p || F)) /\ (q || ~~(p || F))
⇒ logic.propositional.idempandq || ~~(p || F)
⇒ logic.propositional.notnotq || p || F
⇒ logic.propositional.falsezeroorq || p