Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

~~((F /\ r) || ((q || ~~(p || F)) /\ (q || ~~(p || F))))

⇒ logic.propositional.notnot

(F /\ r) || ((q || ~~(p || F)) /\ (q || ~~(p || F)))

⇒ logic.propositional.falsezeroand

F || ((q || ~~(p || F)) /\ (q || ~~(p || F)))

⇒ logic.propositional.falsezeroor

(q || ~~(p || F)) /\ (q || ~~(p || F))

⇒ logic.propositional.idempand

q || ~~(p || F)

⇒ logic.propositional.notnot

q || p || F

⇒ logic.propositional.falsezeroor

q || p