Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

~~((F /\ (r || F)) || q || ~~(p /\ p))

⇒ logic.propositional.notnot

(F /\ (r || F)) || q || ~~(p /\ p)

⇒ logic.propositional.absorpand

F || q || ~~(p /\ p)

⇒ logic.propositional.falsezeroor

q || ~~(p /\ p)

⇒ logic.propositional.notnot

q || (p /\ p)

⇒ logic.propositional.idempand

q || p