Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

~~(((~(p -> q) /\ ~q) || F) -> p)

⇒ logic.propositional.notnot

((~(p -> q) /\ ~q) || F) -> p

⇒ logic.propositional.falsezeroor

(~(p -> q) /\ ~q) -> p

⇒ logic.propositional.defimpl

~(~(p -> q) /\ ~q) || p

⇒ logic.propositional.demorganand

~~(p -> q) || ~~q || p

⇒ logic.propositional.notnot

(p -> q) || ~~q || p

⇒ logic.propositional.defimpl

~p || q || ~~q || p

⇒ logic.propositional.notnot

~p || q || q || p

⇒ logic.propositional.idempor

~p || q || p