Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

~~(((F /\ r) || q || ~~(p || F)) /\ ((F /\ r) || q || ~~(p || F)))

⇒ logic.propositional.notnot

((F /\ r) || q || ~~(p || F)) /\ ((F /\ r) || q || ~~(p || F))

⇒ logic.propositional.idempand

(F /\ r) || q || ~~(p || F)

⇒ logic.propositional.falsezeroand

F || q || ~~(p || F)

⇒ logic.propositional.falsezeroor

q || ~~(p || F)

⇒ logic.propositional.notnot

q || p || F

⇒ logic.propositional.falsezeroor

q || p