Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
~(~q /\ ~(p -> q)) || p || F
⇒ logic.propositional.demorganand~~q || ~~(p -> q) || p || F
⇒ logic.propositional.falsezeroor~~q || ~~(p -> q) || p
⇒ logic.propositional.notnotq || ~~(p -> q) || p
⇒ logic.propositional.notnotq || (p -> q) || p
⇒ logic.propositional.defimplq || ~p || q || p