Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

~(~q /\ ~(p -> q)) || F || (p /\ T)

⇒ logic.propositional.demorganand

~~q || ~~(p -> q) || F || (p /\ T)

⇒ logic.propositional.falsezeroor

~~q || ~~(p -> q) || (p /\ T)

⇒ logic.propositional.notnot

q || ~~(p -> q) || (p /\ T)

⇒ logic.propositional.notnot

q || (p -> q) || (p /\ T)

⇒ logic.propositional.defimpl

q || ~p || q || (p /\ T)

⇒ logic.propositional.truezeroand

q || ~p || q || p