Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
![](http://ideas.cs.uu.nl/images/external.png)
~(F || ~p) || (((F /\ r) || q) /\ ((F /\ r) || q))
⇒ logic.propositional.idempand~(F || ~p) || (F /\ r) || q
⇒ logic.propositional.falsezeroand~(F || ~p) || F || q
⇒ logic.propositional.falsezeroor~(F || ~p) || q