Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

~(F || p) -> ((F /\ r) || q)

⇒ logic.propositional.falsezeroand

~(F || p) -> (F || q)

⇒ logic.propositional.falsezeroor

~p -> (F || q)

⇒ logic.propositional.falsezeroor

~p -> q

⇒ logic.propositional.defimpl

~~p || q

⇒ logic.propositional.notnot

p || q