Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

~(F /\ r) -> ~~(q || ~~((F || ~~p) /\ ~~p))

⇒ logic.propositional.falsezeroand

~F -> ~~(q || ~~((F || ~~p) /\ ~~p))

⇒ logic.propositional.notfalse

T -> ~~(q || ~~((F || ~~p) /\ ~~p))

⇒ logic.propositional.notnot

T -> (q || ~~((F || ~~p) /\ ~~p))

⇒ logic.propositional.notnot

T -> (q || ((F || ~~p) /\ ~~p))

⇒ logic.propositional.absorpand

T -> (q || ~~p)

⇒ logic.propositional.notnot

T -> (q || p)

⇒ logic.propositional.defimpl

~T || q || p

⇒ logic.propositional.nottrue

F || q || p

⇒ logic.propositional.falsezeroor

q || p