Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

q || ~~(p || p) || (F /\ (r || F))

⇒ logic.propositional.absorpand

q || ~~(p || p) || F

⇒ logic.propositional.falsezeroor

q || ~~(p || p)

⇒ logic.propositional.notnot

q || p || p

⇒ logic.propositional.idempor

q || p