Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

T /\ ((~q /\ (F || ~((p -> q) /\ (p -> q)))) -> p)

⇒ logic.propositional.truezeroand

(~q /\ (F || ~((p -> q) /\ (p -> q)))) -> p

⇒ logic.propositional.falsezeroor

(~q /\ ~((p -> q) /\ (p -> q))) -> p

⇒ logic.propositional.idempand

(~q /\ ~(p -> q)) -> p

⇒ logic.propositional.defimpl

~(~q /\ ~(p -> q)) || p

⇒ logic.propositional.demorganand

~~q || ~~(p -> q) || p

⇒ logic.propositional.notnot

q || ~~(p -> q) || p

⇒ logic.propositional.notnot

q || (p -> q) || p

⇒ logic.propositional.defimpl

q || ~p || q || p