Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

F || q || (~p -> ((F /\ r) || q || ~~(p || p)))

⇒ logic.propositional.falsezeroand

F || q || (~p -> (F || q || ~~(p || p)))

⇒ logic.propositional.falsezeroor

F || q || (~p -> (q || ~~(p || p)))

⇒ logic.propositional.notnot

F || q || (~p -> (q || p || p))

⇒ logic.propositional.idempor

F || q || (~p -> (q || p))

⇒ logic.propositional.defimpl

F || q || ~~p || q || p

⇒ logic.propositional.notnot

F || q || p || q || p