Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

F || q || ((~~p || F) /\ (~~p || r)) || ((q || ~~p) /\ T)

⇒ logic.propositional.falsezeroor

F || q || (~~p /\ (~~p || r)) || ((q || ~~p) /\ T)

⇒ logic.propositional.absorpand

F || q || ~~p || ((q || ~~p) /\ T)

⇒ logic.propositional.notnot

F || q || p || ((q || ~~p) /\ T)

⇒ logic.propositional.truezeroand

F || q || p || q || ~~p

⇒ logic.propositional.notnot

F || q || p || q || p