Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
F || q || ((q || ~~p || ~~p || (F /\ r)) /\ (q || ~~p || ~~p || (F /\ r)))
⇒ logic.propositional.idempandF || q || q || ~~p || ~~p || (F /\ r)
⇒ logic.propositional.falsezeroandF || q || q || ~~p || ~~p || F
⇒ logic.propositional.falsezeroorF || q || q || ~~p || ~~p
⇒ logic.propositional.idemporF || q || q || ~~p
⇒ logic.propositional.notnotF || q || q || p