Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

F || (T /\ ((~q /\ ~((p -> q) || F)) -> p))

⇒ logic.propositional.truezeroand

F || ((~q /\ ~((p -> q) || F)) -> p)

⇒ logic.propositional.falsezeroor

F || ((~q /\ ~(p -> q)) -> p)

⇒ logic.propositional.defimpl

F || ~(~q /\ ~(p -> q)) || p

⇒ logic.propositional.demorganand

F || ~~q || ~~(p -> q) || p

⇒ logic.propositional.notnot

F || q || ~~(p -> q) || p

⇒ logic.propositional.notnot

F || q || (p -> q) || p

⇒ logic.propositional.defimpl

F || q || ~p || q || p