Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
![](http://ideas.cs.uu.nl/images/external.png)
F || (F /\ r) || q || (~~(F || p) /\ ~~(F || p))
⇒ logic.propositional.idempandF || (F /\ r) || q || ~~(F || p)
⇒ logic.propositional.notnotF || (F /\ r) || q || F || p
⇒ logic.propositional.falsezeroorF || (F /\ r) || q || p