Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

F || (F /\ r) || q || ((F || ~~p) /\ (F || ~~p))

⇒ logic.propositional.idempand

F || (F /\ r) || q || F || ~~p

⇒ logic.propositional.falsezeroor

F || (F /\ r) || q || ~~p

⇒ logic.propositional.notnot

F || (F /\ r) || q || p