Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
![](http://ideas.cs.uu.nl/images/external.png)
F || (F /\ r) || ((q || ~~(p /\ p)) /\ (q || ~~(p /\ p)))
⇒ logic.propositional.idempandF || (F /\ r) || q || ~~(p /\ p)
⇒ logic.propositional.notnotF || (F /\ r) || q || (p /\ p)
⇒ logic.propositional.idempandF || (F /\ r) || q || p