Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

F || ((~q /\ ~(p -> q)) -> p)
logic.propositional.defimpl
F || ~(~q /\ ~(p -> q)) || p
logic.propositional.demorganand
F || ~~q || ~~(p -> q) || p
logic.propositional.falsezeroor
~~q || ~~(p -> q) || p
logic.propositional.notnot
q || ~~(p -> q) || p
logic.propositional.notnot
q || (p -> q) || p
logic.propositional.defimpl
q || ~p || q || p