Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
F || ((q || (~~p /\ ~~p) || F) /\ (q || (~~p /\ ~~p) || r)) || q || (~~p /\ ~~p)
⇒ logic.propositional.falsezeroorF || ((q || (~~p /\ ~~p)) /\ (q || (~~p /\ ~~p) || r)) || q || (~~p /\ ~~p)
⇒ logic.propositional.absorpandF || q || (~~p /\ ~~p) || q || (~~p /\ ~~p)
⇒ logic.propositional.idempandF || q || ~~p || q || (~~p /\ ~~p)
⇒ logic.propositional.idempandF || q || ~~p || q || ~~p
⇒ logic.propositional.idemporF || q || ~~p
⇒ logic.propositional.notnotF || q || p