Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

F || ((F || q || ~~p) /\ (r || q || ~~p))

⇒ logic.propositional.falsezeroor

F || ((q || ~~p) /\ (r || q || ~~p))

⇒ logic.propositional.absorpand

F || q || ~~p

⇒ logic.propositional.notnot

F || q || p