Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

F || ((F || (~q /\ ~(p -> q))) -> p)

⇒ logic.propositional.falsezeroor

(F || (~q /\ ~(p -> q))) -> p

⇒ logic.propositional.falsezeroor

(~q /\ ~(p -> q)) -> p

⇒ logic.propositional.defimpl

~(~q /\ ~(p -> q)) || p

⇒ logic.propositional.demorganand

~~q || ~~(p -> q) || p

⇒ logic.propositional.notnot

q || ~~(p -> q) || p

⇒ logic.propositional.notnot

q || (p -> q) || p

⇒ logic.propositional.defimpl

q || ~p || q || p