Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

F || (((F /\ (r || F)) || q || ~~p) /\ ((F /\ r) || q || ~~p))

⇒ logic.propositional.absorpand

F || ((F || q || ~~p) /\ ((F /\ r) || q || ~~p))

⇒ logic.propositional.falsezeroand

F || ((F || q || ~~p) /\ (F || q || ~~p))

⇒ logic.propositional.falsezeroor

(F || q || ~~p) /\ (F || q || ~~p)

⇒ logic.propositional.idempand

F || q || ~~p

⇒ logic.propositional.falsezeroor

q || ~~p

⇒ logic.propositional.notnot

q || p