Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

(~(q -> (r || F)) /\ ~(q -> (r || F))) || q || r

⇒ logic.propositional.idempand

~(q -> (r || F)) || q || r

⇒ logic.propositional.falsezeroor

~(q -> r) || q || r

⇒ logic.propositional.defimpl

~(~q || r) || q || r

⇒ logic.propositional.demorganor

(~~q /\ ~r) || q || r

⇒ logic.propositional.notnot

(q /\ ~r) || q || r