Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
![](http://ideas.cs.uu.nl/images/external.png)
(F || q || ~(~p || F)) /\ ((r /\ F) || q || ~(~p || F)) /\ (r || q || ~(~p || F))
⇒ logic.propositional.falsezeroand(F || q || ~(~p || F)) /\ (F || q || ~(~p || F)) /\ (r || q || ~(~p || F))
⇒ logic.propositional.idempand(F || q || ~(~p || F)) /\ (r || q || ~(~p || F))
⇒ logic.propositional.falsezeroor(q || ~(~p || F)) /\ (r || q || ~(~p || F))
⇒ logic.propositional.absorpandq || ~(~p || F)
⇒ logic.propositional.falsezeroorq || ~~p
⇒ logic.propositional.notnotq || p