Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
(F || ((q || ~~(p || p)) /\ (q || ~~(p || p)))) /\ (r || ((q || ~~(p || p)) /\ (q || ~~(p || p))))
⇒ logic.propositional.falsezeroor(q || ~~(p || p)) /\ (q || ~~(p || p)) /\ (r || ((q || ~~(p || p)) /\ (q || ~~(p || p))))
⇒ logic.propositional.absorpand(q || ~~(p || p)) /\ (q || ~~(p || p))
⇒ logic.propositional.idempandq || ~~(p || p)
⇒ logic.propositional.notnotq || p || p
⇒ logic.propositional.idemporq || p