Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
![](http://ideas.cs.uu.nl/images/external.png)
(F /\ r) || q || ~~p || (F /\ r) || ((q || F || ~~p) /\ (q || F || ~~p))
⇒ logic.propositional.idempand(F /\ r) || q || ~~p || (F /\ r) || q || F || ~~p
⇒ logic.propositional.falsezeroor(F /\ r) || q || ~~p || (F /\ r) || q || ~~p
⇒ logic.propositional.notnot(F /\ r) || q || ~~p || (F /\ r) || q || p