Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
![](http://ideas.cs.uu.nl/images/external.png)
(F /\ r) || q || ~~(p /\ p) || ((F || q) /\ (r || q)) || ~~(p /\ p)
⇒ logic.propositional.falsezeroandF || q || ~~(p /\ p) || ((F || q) /\ (r || q)) || ~~(p /\ p)
⇒ logic.propositional.falsezeroorq || ~~(p /\ p) || ((F || q) /\ (r || q)) || ~~(p /\ p)
⇒ logic.propositional.falsezeroorq || ~~(p /\ p) || (q /\ (r || q)) || ~~(p /\ p)
⇒ logic.propositional.absorpandq || ~~(p /\ p) || q || ~~(p /\ p)
⇒ logic.propositional.idemporq || ~~(p /\ p)
⇒ logic.propositional.notnotq || (p /\ p)
⇒ logic.propositional.idempandq || p