Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
![](http://ideas.cs.uu.nl/images/external.png)
(F /\ r) || q || ~~(F || (p /\ p)) || (F /\ r) || q || ~~(F || (p /\ p))
⇒ logic.propositional.falsezeroandF || q || ~~(F || (p /\ p)) || (F /\ r) || q || ~~(F || (p /\ p))
⇒ logic.propositional.falsezeroandF || q || ~~(F || (p /\ p)) || F || q || ~~(F || (p /\ p))
⇒ logic.propositional.falsezeroorq || ~~(F || (p /\ p)) || F || q || ~~(F || (p /\ p))
⇒ logic.propositional.falsezeroorq || ~~(F || (p /\ p)) || q || ~~(F || (p /\ p))
⇒ logic.propositional.idemporq || ~~(F || (p /\ p))
⇒ logic.propositional.notnotq || F || (p /\ p)
⇒ logic.propositional.falsezeroorq || (p /\ p)
⇒ logic.propositional.idempandq || p