Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
![](http://ideas.cs.uu.nl/images/external.png)
(F /\ r) || q || (~(p /\ p) -> ((F /\ r) || q || ~~(p /\ p)))
⇒ logic.propositional.falsezeroandF || q || (~(p /\ p) -> ((F /\ r) || q || ~~(p /\ p)))
⇒ logic.propositional.falsezeroandF || q || (~(p /\ p) -> (F || q || ~~(p /\ p)))
⇒ logic.propositional.falsezeroorq || (~(p /\ p) -> (F || q || ~~(p /\ p)))
⇒ logic.propositional.falsezeroorq || (~(p /\ p) -> (q || ~~(p /\ p)))
⇒ logic.propositional.idempandq || (~p -> (q || ~~(p /\ p)))
⇒ logic.propositional.notnotq || (~p -> (q || (p /\ p)))
⇒ logic.propositional.idempandq || (~p -> (q || p))
⇒ logic.propositional.defimplq || ~~p || q || p
⇒ logic.propositional.notnotq || p || q || p
⇒ logic.propositional.idemporq || p