Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
![](http://ideas.cs.uu.nl/images/external.png)
(F /\ (r || r)) || ((q || ~~p || F) /\ (q || ~~p || F))
⇒ logic.propositional.idempand(F /\ (r || r)) || q || ~~p || F
⇒ logic.propositional.falsezeroor(F /\ (r || r)) || q || ~~p
⇒ logic.propositional.notnot(F /\ (r || r)) || q || p