Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

((~(q || q) /\ ~(p -> q) /\ ~(p -> q)) -> p) /\ ((~(q || q) /\ ~(p -> q) /\ ~(p -> q)) -> p)
logic.propositional.idempand
(~(q || q) /\ ~(p -> q) /\ ~(p -> q)) -> p
logic.propositional.idempand
(~(q || q) /\ ~(p -> q)) -> p
logic.propositional.idempor
(~q /\ ~(p -> q)) -> p
logic.propositional.defimpl
~(~q /\ ~(p -> q)) || p
logic.propositional.demorganand
~~q || ~~(p -> q) || p
logic.propositional.notnot
q || ~~(p -> q) || p
logic.propositional.notnot
q || (p -> q) || p
logic.propositional.defimpl
q || ~p || q || p