Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
((q || ~~p) /\ (r || q || ~~p)) || ((q || ~~p) /\ (r || q || ~~p))
⇒ logic.propositional.absorpandq || ~~p || ((q || ~~p) /\ (r || q || ~~p))
⇒ logic.propositional.absorpandq || ~~p || q || ~~p
⇒ logic.propositional.idemporq || ~~p
⇒ logic.propositional.notnotq || p