Exercise logic.propositional.dnf
Description
Proposition to DNF
Derivation
![](http://ideas.cs.uu.nl/images/external.png)
((p || q) /\ (r <-> p)) || ((p || q) /\ ((r <-> p) || F))
⇒ logic.propositional.defequiv((p || q) /\ (r <-> p)) || ((p || q) /\ ((r /\ p) || (~r /\ ~p) || F))
⇒ logic.propositional.falsezeroor((p || q) /\ (r <-> p)) || ((p || q) /\ ((r /\ p) || (~r /\ ~p)))