Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

((F || q || ~~(p /\ p)) /\ (r || q || ~~(p /\ p))) || F

⇒ logic.propositional.falsezeroor

(F || q || ~~(p /\ p)) /\ (r || q || ~~(p /\ p))

⇒ logic.propositional.falsezeroor

(q || ~~(p /\ p)) /\ (r || q || ~~(p /\ p))

⇒ logic.propositional.absorpand

q || ~~(p /\ p)

⇒ logic.propositional.notnot

q || (p /\ p)

⇒ logic.propositional.idempand

q || p