Exercise logic.propositional.dnf

Description
Proposition to DNF

Derivation

((F || q) /\ (r || q)) || F || ~~(p /\ p)

⇒ logic.propositional.falsezeroor

((F || q) /\ (r || q)) || ~~(p /\ p)

⇒ logic.propositional.falsezeroor

(q /\ (r || q)) || ~~(p /\ p)

⇒ logic.propositional.absorpand

q || ~~(p /\ p)

⇒ logic.propositional.notnot

q || (p /\ p)

⇒ logic.propositional.idempand

q || p